An altitude of a triangle is a segment from any vertex perpendicular to the line containing the opposite side
Proving a Property of Isosceles Triangles Prove that the median from the vertex angle to the base of an isosceles triangle is an altitude
So, let us find the altitude to BC first
The altitude is the shortest distance from the vertex to its opposite side
In geometry, the altitude is a line that passes through two very specific points on a triangle: a vertex, or corner of a triangle, and its opposite side at a right, or 90-degree, angle
In contrast to the Pythagorean Theorem method, if you have two of the three parts, you can find the height for any triangle! The height or altitude of a triangle depends on which base you use for a measurement
8°; side G U = 17 cm, U D = 37 cm, D G = 21 cm] To calculate the altitude of a triangle, you need to find the area of the triangle
Area of a Triangle = (½ base × height)
Notice that it was necessary to extend the side of the triangle from F through G to intersect with our arc
The video didnt mention it explicitly but it ends up that
So, AP is the altitude of ∆ABC
The distance between a vertex of a triangle and the opposite side is an altitude
Isosceles Triangle is a type of triangle that has two sides or angles of equal measurement
It has several important properties and relations with other parts of the triangle, including its circumcenter, incenter, area, and more